Week1

8.48 A. example size=20 Mean=sum of each(prenominal) valuesn=0+260+356.+13020=693020=346.5 Standard deviation=?x-x2n?170.38 nonpareil is 95% overconfident that the unfeigned mean area devoted to advertisements on a indiscriminately elect page is between 266.76 and 426.24 millimeters squared. 95% presumption train 346.5mean 170.38std. dev. 20n 2.093t (df = 19) 79.740half-width 426.240upper confidence rig 266.760 refuse confidence limit B. atomic number 7 might be an recognize since we dont spot if this sample of 20 was chosen randomly. Also, the data is not continuous, and out-of-pocket to the two zero values, commonplaceity is an issue. C. ?=170.38 confidence level=99%=0.99 z1-c2=z1-0.992=z0.012=z0.005=2.576 Margin of error=10 Sample Size n=zE2 =170.38*2.576102 =1926.322269 D. 99% confidence level is panache too narrow for a sample size of 20, and unitary which is unknown to be normal or even chosen randomly. A be tter level would be 90%, or lower. 8.64 A. Sample Size=773 Unpopped kernels determine=86 p=86773=0.1112548512?0.1113 1-p=q=1-86773=687773=0.8887451488?0.8888 self-reliance interval level=90%=0.90 ?=1-0.9=0.1 z?2=z0.12=z0.05=1.645 bureau interval = p z?2p(1-p)n =0.1113±1.6450.1113*0.8888773 =0.1113-1.6450.1113*0.8888773,0.1113+1.6450.1113*0.8888773 =0.1113-1.6450.09892344773,0.1113+1.6450.09892344773 =0.

1113-1.6451.279734023×10-4,0.1113+1.6451.279734023×10-4 =0.1113-0.0186091167,0.1113+0.0186091167 =0.0926908833, 0.1299091167 ?0.093, 0.130±0.019 One can be 90% confident that the true equilibrium of unpopped kernels is between 0.093 and 0.130. 90%con! fidence level 0.1113 relation 773n 1.645z 0.019half-width 0.130upper confidence limit 0.093lower confidence limit (b) n*p>5 AND n*1-p>5 773*0.1113>5---86.0349>5 current! 773*0.8888>5---687.0424>5 TRUE! Normality is confirmed. (c) - The real Quick regularise works when p should be neighboring to 0.5. Out proportion is 0.1113, which isnt close to 0.5, so the Very...If you require to get a full essay, order it on our website: BestEssayCheap.com

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